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JEE Mains · Physics · STD 12 - Electric potential and capacitance
  • JEE Mains 2024
  • Hard
  • MCQ

Two identical capacitors have same capacitance \(C\). One of them is charged to the potential \(\mathrm{V}\) and other to the potential \(2 \mathrm{~V}\). The negative ends of both are connected together. When the positive ends are also joined together, the decrease in energy of the combined system is _______.

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Answer & Solution

Correct Answer

(A) \(\frac{1}{4} \mathrm{CV}^2\)

Step-by-step Solution

Detailed explanation

\(\mathrm{V}_{\mathrm{C}}-\frac{\mathrm{q}_{\text {net }}}{\mathrm{C}_{\text {net }}}=\frac{\mathrm{CV}+2 \mathrm{CV}}{2 \mathrm{C}}\)

\(\mathrm{V}_{\mathrm{C}}=\frac{3 \mathrm{~V}}{2}\)

Loss of energy

\(=\frac{1}{2} \mathrm{CV}^2+\frac{1}{2} \mathrm{C}(2 \mathrm{~V})^2-\frac{1}{2} 2 \mathrm{C}\left(\frac{3 \mathrm{~V}}{2}\right)^2\)

\(=\left(\frac{\mathrm{CV}^2}{4}\right)\)

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