ExamBro
ExamBro
JEE Mains · Physics · STD 11 - Work,energy,power and collision
  • JEE Mains 2023
  • Medium
  • Numerical

A lift of mass \(M =500\,kg\) is descending with speed of \(2\,ms ^{-1}\). Its supporting cable begins to slip thus allowing it to fall with a constant acceleration of \(2\,ms ^{-2}\). The kinetic energy of the lift at the end of fall through to a distance of \(6 m\) will be \(...........kJ.\)

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(A) \(7\)

Step-by-step Solution

Detailed explanation

\(v ^2 = u ^2+2 as\)

\(=2^2+2(2)(6)\)

\(=4+24=28\)

\(KE =\frac{1}{2} mv ^2\)

\(=\frac{1}{2}(500) 28\)

\(=7000\,J\)

\(=7\,kJ\)

Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app