JEE Mains · Physics · STD 11 - Work,energy,power and collision
- JEE Mains 2023
- Medium
- Numerical
A lift of mass \(M =500\,kg\) is descending with speed of \(2\,ms ^{-1}\). Its supporting cable begins to slip thus allowing it to fall with a constant acceleration of \(2\,ms ^{-2}\). The kinetic energy of the lift at the end of fall through to a distance of \(6 m\) will be \(...........kJ.\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(7\)
Step-by-step Solution
Detailed explanation
\(v ^2 = u ^2+2 as\)
\(=2^2+2(2)(6)\)
\(=4+24=28\)
\(KE =\frac{1}{2} mv ^2\)
\(=\frac{1}{2}(500) 28\)
\(=7000\,J\)
\(=7\,kJ\)
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