JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
At \(30^{\circ}\,C\), the half life for the decomposition of \(AB _{2}\) is \(200\,s\) and is independent of the initial concentration of \(AB _{2}\). The time required for \(80 \%\) of the \(AB _{2}\) to decompose is \(....s\) (Given: \(\log 2=0.30;\log 3=0.48)\)
- A \(200\)
- B \(323\)
- C \(467\)
- D \(532\)
Answer & Solution
Correct Answer
(C) \(467\)
Step-by-step Solution
Detailed explanation
\(T _{1 / 2}=200 s\) and \(1^{\text {st }}\) order reaction \(K =\frac{2.303 \log 2}{200}=\frac{2.303}{ t } \log \frac{ A _{0}}{0.2 A _{0}}\) \(\frac{\log 2}{200}=\frac{1}{t} \log 5\) \(t =\frac{7}{3} \times 200=466.67 s =467\,s\)
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