JEE Mains · Chemistry · STD 11 - 8.3. Organic chemistry purification and characterization
In sulphur estimation. \(0.471\,g\) of an organic compound gave \(1.4439\,g\) of barium sulphate.The percentage of sulphur in the compound is \(.............\)(Nearest Integer)(Given: Atomic mass Ba: \(137 u : S : 32 u , O : 16 u\) )
- A \(41\)
- B \(42\)
- C \(40\)
- D \(38\)
Answer & Solution
Correct Answer
(B) \(42\)
Step-by-step Solution
Detailed explanation
\(\%\) sulphur \(=\frac{32}{233} \times \frac{\text { weight of } BaSO _4 \text { formed }}{\text { weight of organic compound }} \times 100\) \(=\frac{32}{233} \times \frac{1.4439}{0.471} \times 100\) \(=42.10\) Nearest integer \(42\)
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