JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
In an experiment to find out the diameter of wire using screw gauge, the following observation were noted. \((a)\) Screw moves \(0.5\,mm\) on main scale in one complete rotation \((b)\) Total divisions on circular scale \(=50\) \((c)\) Main scale reading is \(2.5\,mm\) \((d)\) \(45^{\text {th }}\) division of circular scale is in the pitch line \((e)\) Instrument has \(0.03 \;mm\) negative error Then the diameter of wire is \(...........\,mm\)
- A \(2.92\)
- B \(2.54\)
- C \(2.98\)
- D \(3.45\)
Answer & Solution
Correct Answer
(C) \(2.98\)
Step-by-step Solution
Detailed explanation
\(MSR =2.5\,mm\) \(CSR =45 \times \frac{0.5}{50}\,mm\) \(=0.45\,mm\) Diameter reading \(= MSR + CSR -\) zero error \(=2.5+0.45-(-0.03)\) \(=2.98\,mm\)
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Physics
- In a double slit experiment shown in figure, when light of wavelength \(400 \mathrm{~nm}\) is used, dark fringe is observed at \(P\). If \(D=0.2 \mathrm{~m}\). the minimum distance between the slits \(S_1\) and \(S_2\) is ____________ \(mm\).
JEE Mains 2024 Hard - A particle of mass \(2\, kg\) is on a smooth horizontal table and moves in a circular path of radius \(0.6\, m\). The height of the table from the ground is \(0.8\, m\). If the angular speed of the particle is \(12\, rad\, s^{-1}\), the magnitude of its angular momentum about a point on the ground right under the centre of the circle is ........ \(kg\, m^2\,s^{-1}\)JEE Mains 2015 Medium
- A light string passing over a smooth light pulley connects two blocks of masses \(m_1\) and \(m_2\) (where \(m_2>m_1\) ). If the acceleration of the system is \(\frac{\mathrm{g}}{\sqrt{2}}\), then the ratio of the masses \(\frac{\mathrm{m}_1}{\mathrm{~m}_2}\) is _______.JEE Mains 2024 Hard
- Least count of a vernier caliper is \(\frac{1}{20 \mathrm{~N}} \mathrm{~cm}\). The value of one division on the main scale is \(1 \mathrm{~mm}\). Then the number of divisions of main scale that coincide with \(\mathrm{N}\) divisions of vernier scale is _______.JEE Mains 2024 Hard
- Light is incident from a medium into air at two possible angles of incidence \((A)\, 20^o\) and \((B)\, 40^o\) . In the medium light travels \(3.0\, cm\) in \(0.2\, ns\). The ray willJEE Mains 2013 Hard
- In a Young’s double slit experiment, the slits are placed \(0.320\,mm\) apart. Light of wavelength \(\lambda = 500\,nm\) is incident on the slits. The total number of bright fringes that are observed in the angular range \( - {30^o} \le \theta \le {30^o}\) isJEE Mains 2019 Medium
More PYQs from JEE Mains
- The electric field in a region is given by \(\vec E = \frac{3}{5}{E_0}\hat i + \frac{4}{5}{E_0}\hat j\) and \(E_0 = 2\times10^3\, N/C\). Then, the flux of this field through a rectangular surface of area \(0.2\, m^2\) parallel to the \(y-z\) plane is......\(\frac{{N - {m^2}}}{C}\)JEE Mains 2021 Medium
- Let \(f(x)=a x^{2}+b x+c\) be such that \(f(1)=3, f(-2)\) \(=\lambda\) and \(f (3)=4\). If \(f (0)+ f (1)+ f (-2)+ f (3)=14\), then \(\lambda\) is equal to\(...\)JEE Mains 2022 Hard
- Let \(y = y(x)\) be the solution of the differential equation, \(x\frac{{dy}}{{dx}} + y = x\,{\log _e}\,x,\,\left( {x > 1} \right)\) If \(2y(2) = log_e\, 4 -1\), then \(y(e)\) is equal toJEE Mains 2019 Hard
- A particle is moving in one dimension (along \(\mathrm{x}\) axis) under the action of a variable force. It's initial position was \(16 \mathrm{~m}\) right of origin. The variation of its position ( \(\mathrm{x}\) ) with time ( \(\mathrm{t})\) is given as \(\mathrm{x}=-3 \mathrm{t}^3+18 \mathrm{t}^2+16 \mathrm{t}\), where \(\mathrm{x}\) is in \(\mathrm{m}\) and \(\mathrm{t}\) is in \(\mathrm{s}\). The velocity of the particle when its acceleration becomes zero is _______ \(\mathrm{m} / \mathrm{s}.\)JEE Mains 2024 Hard
- A particle of mass \(10\,g\) moves in a straight line with retarcation \(2x\), where \(x\) is the displacement in \(SI\) units. Its loss of kinetic energy for above displacement is \(\left(\frac{10}{x}\right)^{- n }\, J\). The value of \(n\) will be \(............\).JEE Mains 2023 Hard
- Let \(A=\{1,3,7,9,11\}\) and \(B=\{2,4,5,7,8,10,12\}\). Then the total number of one-one maps \(\mathrm{f}: \mathrm{A} \rightarrow \mathrm{B}\), such that \(\mathrm{f}(1)+\mathrm{f}(3)=14\), is :JEE Mains 2024 Hard