प्रकाश स्रोत \(S_1\) की शक्ति का प्रकाश स्रोत \(S_2\) की शक्ति से अनुपात \(2\) है। \(S_1\), 600 nm पर \(2 \times 10^{15}\) फोटॉन प्रति सेकंड उत्सर्जित कर रहा है। यदि स्रोत \(S_2\) की तरंगदैर्ध्य 300 nm है, तो \(S_2\) द्वारा प्रति सेकंड उत्सर्जित फोटॉनों की संख्या _______ \(\times 10^{14}\) है।

A 10
B 5
C 15
D 20

Verified Solution

Answer & Solution

Correct Answer

(B) 5

Step-by-step Solution

Detailed explanation

चूँकि किसी स्रोत द्वारा उत्सर्जित शक्ति को इस प्रकार व्यक्त किया जाता है \(\begin{aligned} & =\frac{\text { Total energy emitted }}{\text { time }} \\ & =\frac{\left(E_1 \text { photon }\right) \times \text { Number of photons }(N)}{t} \\ & P_1=\left(E_1\right) n \end{aligned}\)…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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