JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter
The ratio of the power of a light source \(S_1\) to that the light source \(S_2\) is \(2 . S_1\) is emitting \(2 \times 10^{15}\) photons per second at 600 nm . If the wavelength of the source \(S_2\) is 300 nm , then the number of photons per second emitted by \(S_2\) is _______ \(\times 10^{14}\).
- A 10
- B 5
- C 15
- D 20
Answer & Solution
Correct Answer
(B) 5
Step-by-step Solution
Detailed explanation
Since power emitting by a source is given as \(\begin{aligned} & =\frac{\text { Total energy emitted }}{\text { time }} \\ & =\frac{\left(E_1 \text { photon }\right) \times \text { Number of photons }(N)}{t} \\ & P_1=\left(E_1\right) n \end{aligned}\)…
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