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JEE Mains · Maths · STD 12 - 9. differential equations

माना अवकल समीकरण \(\left[\frac{x}{\sqrt{x^2-y^2}}+e^{\frac{y}{x}}\right] x \frac{d y}{d x}=x+\left[\frac{x}{\sqrt{x^2-y^2}}+e^{\frac{y}{x}}\right] y\) का हल वक्र \(y = y ( x )\) हो जो \((1,0)\) तथा \((2 \alpha, \alpha), \alpha > 0\) से होकर गुजरता हो तब \(\alpha\) बराबर होगा

  1. A \(\frac{1}{2} \exp \left(\frac{\pi}{6}+\sqrt{ e }-1\right)\)
  2. B \(\frac{1}{2} \exp \left(\frac{\pi}{3}+\sqrt{ e }-1\right)\)
  3. C \(\exp \left(\frac{\pi}{6}+\sqrt{ e }+1\right)\)
  4. D \(2 \exp \left(\frac{\pi}{3}+\sqrt{ e }-1\right)\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{1}{2} \exp \left(\frac{\pi}{6}+\sqrt{ e }-1\right)\)

Step-by-step Solution

Detailed explanation

\(\left(\frac{x}{\sqrt{x^{2}-y^{2}}}+e^{\frac{y}{x}}\right) x \frac{d y}{d x}=x+\left(\frac{x}{\sqrt{x^{2} y^{2}}}+e^{\frac{y}{x}}\right) y\) \(e^{\frac{y}{x}}(x d y-y d x)+\frac{x}{\sqrt{x^{2}-y^{2}}}(x d y-y d x)=x d x\) Dividing both side by \(x ^{2}\)…
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