JEE Mains · Maths · STD 12 - 9. differential equations
Let the solution curve \(y = y ( x )\) of the differential equation, \(\left[\frac{x}{\sqrt{x^{2}-y^{2}}}+e^{\frac{y}{x}}\right] x \frac{d y}{d x}=x+\left[\frac{x}{\sqrt{x^{2}-y^{2}}}+e^{\frac{y}{x}}\right] y\) pass through the points \((1,0)\) and \((2 \alpha, \alpha), \alpha>0\). Then \(\alpha\) is equal to
- A \(\frac{1}{2} \exp \left(\frac{\pi}{6}+\sqrt{ e }-1\right)\)
- B \(\frac{1}{2} \exp \left(\frac{\pi}{3}+\sqrt{ e }-1\right)\)
- C \(\exp \left(\frac{\pi}{6}+\sqrt{ e }+1\right)\)
- D \(2 \exp \left(\frac{\pi}{3}+\sqrt{ e }-1\right)\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{2} \exp \left(\frac{\pi}{6}+\sqrt{ e }-1\right)\)
Step-by-step Solution
Detailed explanation
\(\left(\frac{x}{\sqrt{x^{2}-y^{2}}}+e^{\frac{y}{x}}\right) x \frac{d y}{d x}=x+\left(\frac{x}{\sqrt{x^{2} y^{2}}}+e^{\frac{y}{x}}\right) y\) \(e^{\frac{y}{x}}(x d y-y d x)+\frac{x}{\sqrt{x^{2}-y^{2}}}(x d y-y d x)=x d x\) Dividing both side by \(x ^{2}\)…
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