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JEE Mains · Maths · STD 12 - 10. vector algebra

माना \(\vec{a}=\hat{i}+\alpha \hat{j}+\beta \hat{k}, \alpha, \beta \in R\) है। माना एक सदिश \(\overrightarrow{\mathrm{b}}\) इस प्रकार है कि \(\overrightarrow{\mathrm{a}}\) तथा \(\overrightarrow{\mathrm{b}}\) के बीच कोण \(\frac{\pi}{4}\) है तथा \(|\vec{b}|^2=6\) है। यदि \(\vec{a} \cdot \vec{b}=3 \sqrt{2}\) है, तो \(\left(\alpha^2+\beta^2\right)|\overrightarrow{\mathrm{a}} \times \overrightarrow{\mathrm{b}}|^2\) = ...........

  1. A \(90\)
  2. B \(75\)
  3. C \(95\)
  4. D \(85\)
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Answer & Solution

Correct Answer

(A) \(90\)

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Detailed explanation

\(|\vec{b}|^2=6 ;|\vec{a}||\vec{b}| \cos \theta=3 \sqrt{2}\) \(|\vec{a}|^2|\vec{b}|^2 \cos ^2 \theta=18\) \(|\vec{a}|^2=6\) Also \(1+\alpha^2+\beta^2=6\) \(\left(\alpha^2+\beta^2\right)|\vec{a}|^2|\vec{b}|^2 \sin ^2 \theta\) \(=(5)(6)(6)\left(\frac{1}{2}\right)\)…
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