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JEE Mains · Maths · STD 12 - 13. probability

एक न्यास पासे को छः प्राप्त होने तक बार-बार फैंका जाता है। माना पासे को फेंकने की आवश्यक संख्या \(\mathrm{X}\) है तथा माना \(\mathrm{a}=\mathrm{P}(\mathrm{X}=3), \mathrm{b}=\mathrm{P}(\mathrm{X} \geq 3)\) तथा \(c=P(X \geq 6 \mid X>3)\). तो \(\frac{b+c}{a}\) = ...........

  1. A \(19\)
  2. B 12
  3. C \(14\)
  4. D \(16\)
Verified Solution

Answer & Solution

Correct Answer

(B) 12

Step-by-step Solution

Detailed explanation

\( a=P(X=3)=\frac{5}{6} \times \frac{5}{6} \times \frac{1}{6}=\frac{25}{216} \) \( b=P(X \geq 3)=\frac{5}{6} \times \frac{5}{6} \times \frac{1}{6}+\left(\frac{5}{6}\right)^3 \cdot \frac{1}{6}+\left(\frac{5}{6}\right)^4 \cdot \frac{1}{6}+\ldots \ldots \)…
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