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JEE Mains · Maths · STD 11 - 8. sequence and series

\(\frac{3 \times 1^{3}}{1^{2}}+\frac{5 \times\left(1^{3}+2^{3}\right)}{1^{2}+2^{2}}+\frac{7 \times\left(1^{3}+2^{3}+3^{3}\right)}{1^{2}+2^{2}+3^{2}}+\ldots \ldots\) में दसवें पद तक का योगफल हैं

  1. A \(620\)
  2. B \(660\)
  3. C \(680\)
  4. D \(600\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(660\)

Step-by-step Solution

Detailed explanation

\({T_n} = \frac{{\left( {3 + \left( {n - 1} \right) \times 2} \right)\left( {{1^3} + {2^3} + .... + {n^3}} \right)}}{{\left( {1 + {2^2} + .... + {n^2}} \right)}}\) \( = \frac{3}{2}n\left( {n + 1} \right)\) \({S_n} = \sum {{T_n}} \)…
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