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JEE Mains · Maths · STD 12 - 11. three dimension geometry

बिंदु \((-1,2,3)\) की रेखाओं \(\overrightarrow{\mathrm{r}}=(\hat{\mathrm{i}}-\hat{\mathrm{j}})+\lambda(2 \hat{\mathrm{i}}+\hat{\mathrm{k}})\) तथा \(\overrightarrow{\mathrm{r}}=(2 \hat{\mathrm{i}}-\hat{\mathrm{j}})+\mu(\hat{\mathrm{i}}-\hat{\mathrm{j}}+\hat{\mathrm{k}})\) के बीच न्यूनतम दूरी की रेखा के समांतर समतल \(\overrightarrow{\mathrm{r}} \cdot(\hat{\mathrm{i}}-2 \hat{\mathrm{j}}+3 \hat{\mathrm{k}})=10\) से दूरी है:

  1. A \(3 \sqrt{6}\)
  2. B \(3 \sqrt{5}\)
  3. C \(2 \sqrt{6}\)
  4. D \(2 \sqrt{5}\)
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Answer & Solution

Correct Answer

(C) \(2 \sqrt{6}\)

Step-by-step Solution

Detailed explanation

Let \(L _1: \overrightarrow{ r }=(\hat{ i }-\hat{ j })+\lambda(2 \hat{ i }+\hat{ k })\) \(L_2: \overrightarrow{ r }=(2 \hat{ i }-\hat{ j })+\mu(\hat{ i }-\hat{ j }+\hat{ k })\)…
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