ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Maths · STD 12 - 11. three dimension geometry

રેખા ઓ \(\vec{r}=(\hat{i}-\hat{j})+\lambda(2 \hat{i}+\hat{k})\) અને \(\vec{r}=(2 \hat{i}-\hat{j})+\mu(\hat{i}-\hat{j}+\hat{k})\) વચ્ચે ન્યૂનત્તમ અંતર ની રેખાની દિશામાં બિંદુુ \((-1,2,3,\)) નું સમતલ \(\vec{r} \cdot(\hat{i}-2 \hat{j}+3 \hat{k})=10\) થી અંતર \(...........\) છે.

  1. A \(3 \sqrt{6}\)
  2. B \(3 \sqrt{5}\)
  3. C \(2 \sqrt{6}\)
  4. D \(2 \sqrt{5}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(2 \sqrt{6}\)

Step-by-step Solution

Detailed explanation

Let \(L _1: \overrightarrow{ r }=(\hat{ i }-\hat{ j })+\lambda(2 \hat{ i }+\hat{ k })\) \(L_2: \overrightarrow{ r }=(2 \hat{ i }-\hat{ j })+\mu(\hat{ i }-\hat{ j }+\hat{ k })\)…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app