ચાંદી ઘનમાં ચાંદીનો પરમાણુ અમુક દિશામાં \( 10^{12}\) \(Sec\) ની આવૃત્તિથી સરળ આવર્તગતિ ( દોલન ) કરે છે.એક પરમાણુને બીજા પરમાણુ સાથે જોડતા બંધ ( બોન્ડ ) માટેના બળ અચળાંકનું મૂલ્ય કેટલા .............. \(\mathrm{N/m}\) હશે? ( ચાંદી માટેનો અણુભાર = \(108\) અને એવોગેડ્રો અંક = \(6.02 \times 10^{23}\) \(gm \ mole^{ -1}\) )

A \(7.1\)
B \(2.2 \)
C \(5.5 \)
D \(6.4 \)

Verified Solution

Answer & Solution

Correct Answer

(A) \(7.1\)

Step-by-step Solution

Detailed explanation

As we know, frequency in \(SHM\) \(\mathrm{f}=\frac{1}{2 \pi} \sqrt{\frac{\mathrm{k}}{\mathrm{m}}}=10^{12}\) where \(\mathrm{m}=\mathrm{mass}\) of one atom Mass of one atom of silver, \(=\frac{108}{\left(6.02 \times 10^{23}\right)} \times 10^{-3} \mathrm{kg}\)…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Explore more questions on app

From JEE Mains

Explore more questions on app