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JEE Mains · Physics · STD 12 - 13. Nuclei

\({ }_6 \mathrm{C}^{12}\) નો પરમાણુ દળાંક \(12.000000 \mathrm{u}\) અને \({ }_6 \mathrm{C}^{13}\) નો દળાંક \(13.003354 \mathrm{u}\) છે. જો ન્યુટ્રોનનું દળ \(1.008665 \mathrm{u}\) હોય તો \({ }_6 \mathrm{C}^{13}\)માંથી ન્યૂટ્રોનને દૂર કરવા માટે જરૂરી ઊર્જા.........હશે.

  1. A  \(62.5\  \mathrm{MeV}\)
  2. B  \(6.25\  \mathrm{MeV}\)
  3. C  \(4.95 \ \mathrm{MeV}\)
  4. D  \(49.5\  \mathrm{MeV}\)
Verified Solution

Answer & Solution

Correct Answer

(C)  \(4.95 \ \mathrm{MeV}\)

Step-by-step Solution

Detailed explanation

\( { }_6 \mathrm{C}^{13}+\text { Energy } \rightarrow{ }_6 \mathrm{C}^{12}+{ }_0 \mathrm{n}^1 \) \( \Delta \mathrm{m}=(12.000000+1.008665)-13.003354 \) \( =-0.00531\ \mathrm{u} \) \( \therefore \text { Energy required }=0.00531 \times 931.5 \mathrm{MeV} \)…
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