\({ }^{235} U \rightarrow{ }^{140} \mathrm{Ce}+{ }^{94} \mathrm{Zr}+n\) ન્યુક્લિયર વિખંડન પ્રક્રિયા માટ વિખંડન ઊર્જા \(Q\) _______ \(\mathrm{MeV}\) હશે. પરમાણ્વીય દળોઃ \({ }^{235} U: 235.0439 U ;{ }^{140} \mathrm{Ce}: 139.9054 u, { }^{94} \mathrm{Zr}: 93.9063 U ; n: 1.0086 U\) અને \(C^2=931 \mathrm{MeV} / u\) આપેલ છે.

Disintegration energy

\(\mathrm{Q} =\left(\mathrm{m}_{\mathrm{k}}-\mathrm{m}_{\mathrm{r}}\right) \mathrm{c}^2\)

\(\mathrm{~m}_{\mathrm{n}}  =235.0439 \mathrm{u}\)

\(\mathrm{m}_{\mathrm{r}}  =139.9054 \mathrm{u}+93.9063 \mathrm{u}+1.0086 \mathrm{u}\)

\(=234.8203 \mathrm{u}\)

\(\mathrm{Q}  =(235.0439 \mathrm{u}-234.8203 \mathrm{u}) \mathrm{c}^2\)

\(=0.2236 \mathrm{c}^2\)

\(=0.2236 \times 931\)

\(\mathrm{Q}  =208.1716\)