\(1000 \mathrm{~kg} / \mathrm{m}^3\) ઘનતાવાળા પ્રવાહીની મુક્ત સપાટીથી 20 cm ઊંડાઈએ 0.1 cm ત્રિજ્યાનો એક હવાનો પરપોટો આવેલો છે. જો પરપોટાની અંદરનું દબાણ વાતાવરણના દબાણ કરતાં \(2100 \mathrm{~N} / \mathrm{m}^2\) વધારે હોય, તો SI એકમમાં પ્રવાહીનું પૃષ્ઠતાણ શોધો (\(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\) લો).

A \(0.1\)
B \(0.05\)
C \(0.02\)
D \(0.25\)

Verified Solution

Answer & Solution

Correct Answer

(B) \(0.05\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & P_1=P_0+\rho g h=P_0+1000 \times 10 \times \frac{20}{100} \\ & \Rightarrow P_1=P_0+2000 \end{aligned}\) આથી, \(P_2-P_1=\frac{2 S}{R}=\left(\frac{2 S}{1 \times 10^{-3}}\right)\) \(\Rightarrow P_2=P_0+2100\) (આપેલ છે)…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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