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JEE Mains · Maths · STD 11 - 12. limits

\(\mathop {\lim }\limits_{x \to 0} \,\frac{{{{\sin }^2}\,x}}{{\sqrt 2  - \sqrt {1 + \cos \,x} }}\) = 

  1. A \(\sqrt 2 \)
  2. B \(4\sqrt 2 \)
  3. C \(4\)
  4. D \(2\sqrt 2 \)
Verified Solution

Answer & Solution

Correct Answer

(B) \(4\sqrt 2 \)

Step-by-step Solution

Detailed explanation

\(\mathop {\lim }\limits_{x \to 0} \frac{{\left( {\frac{{{{\sin }^2}x}}{{{x^2}}}} \right)\left( {\sqrt 2 + \sqrt {1 + \cos x} } \right)}}{{\left( {\frac{{1 - \cos x}}{{{x^2}}}} \right)}}\)…
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