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JEE Mains · Maths · STD 12 - 7.2 definite integral

વિધેય  \(f\) અને \(g\) એ \([0, a]\) પર સતત વિધેય છે કે જેથી \(f(x) = f(a -x)\) અને \(g(x) + g(a -x) = 4\), તો  \(\int\limits_0^a {f\left( x \right)g\left( x \right)dx} \) મેળવો.

  1. A \(4\int\limits_0^a {f\left( x \right)dx} \)
  2. B \(\int\limits_0^a {f\left( x \right)dx} \)
  3. C \(2\int\limits_0^a {f\left( x \right)dx} \)
  4. D \(-3\int\limits_0^a {f\left( x \right)dx} \)
Verified Solution

Answer & Solution

Correct Answer

(C) \(2\int\limits_0^a {f\left( x \right)dx} \)

Step-by-step Solution

Detailed explanation

\({\mathrm{I}=\int_{0}^{\mathrm{a}} \mathrm{f}(\mathrm{x}) \mathrm{g}(\mathrm{x}) \mathrm{d} \mathrm{x}=\int_{0}^{\mathrm{a}} \mathrm{f}(\mathrm{a}-\mathrm{x}) \mathrm{g}(\mathrm{a}-\mathrm{x}) \mathrm{d} \mathrm{x}} \)…
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