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JEE Mains · Maths · STD 11 - 7. binomial theoram

જો \({\left( {{x^{\frac{1}{3}}} + \frac{1}{{2{x^{\frac{1}{3}}}}}} \right)^{18}}\,,\,\left( {x > 0} \right),\) ના વિસ્તરણમાં \(x^{-2}\) અને  \(x^{-4}\) ના સહગુણક  અનુક્રમે \(m\) અને \(n\) હોય તો \(\frac{m}{n}\) = ... 

  1. A \(27\)
  2. B \(182\)
  3. C \(\frac{5}{4}\)
  4. D \(\frac{4}{5}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(182\)

Step-by-step Solution

Detailed explanation

\(T_{r+1}=18 C_{r}\left(x^{\frac{1}{3}}\right)^{18-r}\left(\frac{1}{2 x^{\frac{1}{3}}}\right)^{r}\) \(=^{18} C_{r} x^{6-\frac{2 r}{3}} \frac{1}{2^{r}}\)…
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