જો \(x =1\) એ વિધેય \(f(x)=\left(3 x^{2}+a x-2-a\right) e^{x},\) એ નિર્ણાયક કિમત હોય તો

A વિધેય \(f\) એ \(x =1\) આગળ સ્થાનીય ન્યૂનતમ અને \(x =-\frac{2}{3}\) આગળ સ્થાનીય મહત્તમ થાય
B વિધેય \(f\) એ \(x =1\) આગળ સ્થાનીય મહત્તમ અને \(x =-\frac{2}{3}\) આગળ સ્થાનીય ન્યૂનતમ થાય
C વિધેય \(f\) એ \(x =1\) આગળ અને \(x =-\frac{2}{3}\) આગળ સ્થાનીય ન્યૂનતમ થાય
D વિધેય \(f\) એ \(x =1\) આગળ અને \(x =-\frac{2}{3}\) આગળ સ્થાનીય મહત્તમ થાય

Verified Solution

Answer & Solution

Correct Answer

(A) વિધેય \(f\) એ \(x =1\) આગળ સ્થાનીય ન્યૂનતમ અને \(x =-\frac{2}{3}\) આગળ સ્થાનીય મહત્તમ થાય

Step-by-step Solution

Detailed explanation

\(f(x)=\left(3 x^{2}+a x-2-a\right) e^{x}\) \(f^{\prime}(x)=\left(3 x^{2}+a x-2-a\right) e^{x}+e^{x}(6 x+a)\) \(=e^{x}\left(3 x^{2}+x(6+a)-2\right)\) \(f^{\prime}(x)=0\) at \(x=1\) \(\Rightarrow 3+(6+a)-2=0\) \(a=-7\) \(f^{\prime}(x)=e^{x}\left(3 x^{2}-x-2\right)\)…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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