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JEE Mains · Maths · STD 12 - 9. differential equations

ધારોકે \(f\) એ અંતરાલ \((0, \infty)\) માં એવો વિકલનીય વિધેય છે કે જેથી \(f(1)=1\) અને પ્રત્યેક \(x>0\) માટે \(\lim _{\mathrm{t} \rightarrow x} \frac{\mathrm{t}^2 f(x)-x^2 f(\mathrm{t})}{\mathrm{t}-x}=1\). તો \(2 f(2)+3 f(3)=\) ..............

  1. A \(25\)
  2. B \(24\)
  3. C \(26\)
  4. D \(48\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(24\)

Step-by-step Solution

Detailed explanation

\( \lim _{t \rightarrow x} \frac{t^2 f(x)-x^2 f(t)}{t-x}=1 \) \( \lim _{t \rightarrow x} \frac{2 t . f(x)-x^2 f^{\prime}(x)}{1}=1 \) \( 2 x . f(x)-x 2 f^{\prime}(x)=1 \) \( \frac{d y}{d x}-\frac{2}{x} \cdot y=\frac{-1}{x^2} \)…
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