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JEE Mains · Maths · STD 12 - 5. continuity and differentiation

જો \(f(x) = 15-|x -10|;\,\,x \in R.\) તો  \(x\) ની કિમંત નો ગણ મેળવો કે જ્યાં વિધેય \(g(x) = f(f(x))\) એ વિકલનીય ન હોય .

  1. A \(\{5, 10, 15\}\)
  2. B \(\{10\}\)
  3. C \(\{5, 10, 15, 20\}\)
  4. D \(\{10, 15\}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\{5, 10, 15\}\)

Step-by-step Solution

Detailed explanation

\(f\left( x \right) = 15 - \left| {x - 10} \right|,x \in R\) \(f\left( {f\left( x \right)} \right) = 15 - \left| {f\left( x \right) - 10} \right|\) \( = 15 - \left| {15 - \left| {x - 10} \right| - 10} \right|\) \( = 15 - \left| {15 - \left| {x - 10} \right|} \right|\)…
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