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JEE Mains · Maths · STD 11 - 4.2 Quadratic equations and inequations

ધારોકે \(\alpha, \beta\) એ સમીકરણ \(x^{2}-4 \lambda x+5=0\) નાં બીજ છે અને \(\alpha, \gamma\) એ સમીકરણ \(x^{2}-(3 \sqrt{2}+2 \sqrt{3}) x+7+3 \lambda \sqrt{3}=0, \lambda>0\) નાં બીજ છે.જો \(\beta+\gamma=3 \sqrt{2}\) હોય,તો\((\alpha+2 \beta+\gamma)^{2}=\dots\dots\dots\)

  1. A \(95\)
  2. B \(96\)
  3. C \(97\)
  4. D \(98\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(98\)

Step-by-step Solution

Detailed explanation

\(x^{2}-4 \lambda x+5=0\left\langle_{\beta}^{a}\right.\) \(x^{2}-(3 \sqrt{2}+2 \sqrt{3}) x+(7+3 \lambda \sqrt{3})=0\left\langle_{\gamma}^{\alpha}\right.\) \(\alpha+\beta=4 \lambda\) \(\alpha+\gamma=3 \sqrt{2}+2 \sqrt{3}\)…
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