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JEE Mains · Maths · STD 12 - 13. probability

ધારો કે એક યાદચ્છિક ચલ X, \(0,1,2,3\) કિંમતો ધારણ કરે છે, જ્યાં \(\mathrm{P}(\mathrm{X}=0)=\mathrm{P}(\mathrm{X}=1)=\mathrm{p}, \mathrm{P}(\mathrm{X}=2)=\mathrm{P}(\mathrm{X}=3)\) અને \(\mathrm{E}\left(\mathrm{X}^2\right)=2 \mathrm{E}(\mathrm{X})\) છે. તો \(8 \mathrm{p}-1\) નું મૂલ્ય શોધો :

  1. A 0
  2. B 2
  3. C 1
  4. D 3
Verified Solution

Answer & Solution

Correct Answer

(B) 2

Step-by-step Solution

Detailed explanation

\begin{aligned} & 2 p+2 q=\frac{1}{2} \\ & p+q \\ & E\left(x^2\right)=\sum_{i=0}^3 x_i^2 p\left(x_i\right)=0 \cdot p+1 \cdot p+4 \cdot q+9 q \\ & =p+13 q \\ & E(x)=\sum_{i=0}^3 x_i^2 p\left(x_i\right)=0 \cdot p+1 \cdot p+2 q+3 q=p+5 q \\ & p+13 q=2(p+5 q) \\ & p=3 q \\ & \text {…

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