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JEE Mains · Maths · STD 12 - 7.1 indefinite integral

\(\int {\frac{{{{\sin }^8}\,x - {{\cos }^8}\,x}}{{\left( {1 - 2\,{{\sin }^2}\,x\,{{\cos }^2}\,x} \right)}}} dx \) મેળવો. 

  1. A \(\frac{1}{2}\,\sin \,2x + c\)
  2. B \(-\frac{1}{2}\,\sin \,2x + c\)
  3. C \(-\frac{1}{2}\,\sin \,x + c\)
  4. D \( - \sin {^2}\,x + c\)
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Correct Answer

(B) \(-\frac{1}{2}\,\sin \,2x + c\)

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