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JEE Mains · Maths · STD 11 - 13. statistics

ધારોકે \(8\) સંખ્યાઓ \(x, y, 10,12,6,12,4,8\) ના મધ્યક અને વિયરણ અનુક્રમે \(9\) અને \(9.25\) છે. જો \(x > y\) હોય, તો \(3 x-2 y=.........\).

  1. A \(24\)
  2. B \(25\)
  3. C \(23\)
  4. D \(22\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(25\)

Step-by-step Solution

Detailed explanation

\(\frac{x+y+52}{8}=9 \Rightarrow x+y=20\) For variance \(x-9, y-9,3,3,1,-5,-1,-3\) \(\bar{x}=0\) \(\therefore \frac{(x-9)^2+(y-9)^2+54}{8}-0^2=9.25\) \((x-9)^2+(11-x)^2=20\) \(x=7 \text { or } 13 \therefore y=13,7\) \(3 x-2 y=3 \times 13-2 \times 7=25\)
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