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JEE Mains · Maths · STD 11 - 4.2 Quadratic equations and inequations

ધારો કે \(\mathrm{S}=\left\{\sin ^2 2 \theta:\left(\sin ^4 \theta+\cos ^4 \theta\right) x^2+(\sin 2 \theta) x+\left(\sin ^6 \theta+\cos ^6 \theta\right)=0\right.\) ને વાસ્તવિક બીજ છે\(\}\). જો \(\alpha\) અને \(\beta\) અનુક્રમે ગણ \(S\) ના ન્યૂનતમ અને મહત્તમ સભ્યો હોય, તો \(3((\alpha-\) \(\left.2)^2+(\beta-1)^2\right)=\) ..........

  1. A \(4\)
  2. B \(2\)
  3. C \(7\)
  4. D \(9\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(4\)

Step-by-step Solution

Detailed explanation

\( \mathrm{D}=(\sin 2 \theta)^2-4\left(1-\frac{\sin ^2 2 \theta}{2}\right)\left(1-\frac{3}{4} \sin ^2 2 \theta\right) \) \( =(\sin 2 \theta)^2-4\left(1-\frac{5}{4} \sin ^2 2 \theta+\frac{3}{8} \sin ^4 2 \theta\right) \)…
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