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JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola

જો રેખા \(x -2y = 12\) એ ઉપવલય \(\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1\) ના બિંદુ \(\left( {3,\frac{-9}{2}} \right)\) આગળનો સ્પર્શક હોય તો ઉપવલયના નાભીલંબની લંબાઈ = 

  1. A \(12\sqrt 2\)
  2. B \(9\)
  3. C \(8\sqrt 3\)
  4. D \(5\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(9\)

Step-by-step Solution

Detailed explanation

Tangent at \(\left( {3,\frac{{ - 9}}{2}} \right)\) \(\frac{{3x}}{{{a^2}}} - \frac{{9y}}{{2{b^2}}} = 1\) Comparing with \(x - 2y = 12\) \(\frac{3}{{{a^2}}} - \frac{9}{{4{b^2}}} = \frac{1}{{12}}\) \( \Rightarrow a = 6\) and \(b = 3\sqrt 3 \) Length of latus rectum…
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