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JEE Mains · Maths · STD 12 - 11. three dimension geometry

ધારો કે \(\mathrm{P}(\alpha, \beta, \gamma)\) એ બિંદુ \(\mathrm{Q}(1,6,4)\) નું રેખા \(\frac{x}{1}=\frac{y-1}{2}=\frac{z-2}{3}\) પરનું પ્રતિબિંબ છે. તો \(2 \alpha+\beta+\gamma=\) ...............

  1. A \(15\)
  2. B \(16\)
  3. C \(17\)
  4. D \(11\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(11\)

Step-by-step Solution

Detailed explanation

\( \mathrm{A}(t, 2 t+1,3 \mathrm{t}+2) \) \( \overrightarrow{\mathrm{QA}}=(\mathrm{t}-1) \hat{\mathrm{i}}+(2 \mathrm{t}-5) \hat{\mathrm{j}}+(3 \mathrm{t}-2) \hat{\mathrm{k}} \) \( \overrightarrow{\mathrm{QA}} \cdot \overrightarrow{\mathrm{b}}=0 \)…
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