JEE Mains · Maths · STD 12 - 11. three dimension geometry
Let \(\mathrm{P}(\alpha, \beta, \gamma)\) be the image of the point \(\mathrm{Q}(1,6,4)\) in the line \(\frac{x}{1}=\frac{y-1}{2}=\frac{z-2}{3}\). Then \(2 \alpha+\beta+\gamma\) is equal to ..............
- A \(15\)
- B \(16\)
- C \(17\)
- D \(11\)
Answer & Solution
Correct Answer
(D) \(11\)
Step-by-step Solution
Detailed explanation
\( \mathrm{A}(t, 2 t+1,3 \mathrm{t}+2) \) \( \overrightarrow{\mathrm{QA}}=(\mathrm{t}-1) \hat{\mathrm{i}}+(2 \mathrm{t}-5) \hat{\mathrm{j}}+(3 \mathrm{t}-2) \hat{\mathrm{k}} \) \( \overrightarrow{\mathrm{QA}} \cdot \overrightarrow{\mathrm{b}}=0 \)…
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