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JEE Mains · Maths · STD 11 - 7. binomial theoram

જો \(x\) ને \(4\) વડે ભાગતાં શેષ \(3\) મળે, તો \((2020+ x )^{2022}\) ને \(8\) વડે ભાગતાં મળતી શેષ ....... છે.

  1. A \(1\)
  2. B \(6\)
  3. C \(2\)
  4. D \(4\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(1\)

Step-by-step Solution

Detailed explanation

\(x=4 k+3\) \(\therefore(2020+ x )^{2022}=(2020+4 k +3)^{2022}\) \(=(4(505+ k )+3)^{2022}\) \(=(4 \lambda+3)^{2022}=\left(16 \lambda^{2}+24 \lambda+9\right)^{1011}\) \(=\left(8\left(2 \lambda^{2}+3 \lambda+1\right)+1\right)^{1011}\) \(=(8 p +1)^{1011}\) \(\therefore\) Remainder…
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