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JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry

સમાન ચુંબકીય ચાકમાત્રા ધરાવતી જોડ .......છે. [પ.ક્ર.: \(Cr= 24,\,Mn= 25, \,Fe= 26, \,Co= 27\)]

  1. A \([Mn(H_2O)_6]^{2+}\) અને \([Cr(H_2O)_6]^{2+}\)
  2. B \([CoCl_4]^{2-}\) અને \([Fe(H_2O)_6]^{2+}\)
  3. C \([Cr(H_2O)_6]^{2+}\) અને \([CoCl_4]^{2-}\)
  4. D \([Cr(H_2O)_6]^{2+}\) અને \([Fe(H_2O)_6]^{2+}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \([Cr(H_2O)_6]^{2+}\) અને \([Fe(H_2O)_6]^{2+}\)

Step-by-step Solution

Detailed explanation

magnetic moment \(\mu=\sqrt{n(n+2)}\) where \(n\) is the number of unpaired electrons. \(C r^{2+}\) and \(F e^{2+}\) has same number of unpaired electrons \(C r^{2+}=>3 d^{4}\) four unpaired electrons \(F e^{2+}=>3 d^{6}\) four unpaired electrons
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