JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry
The pair having the same magnetic moment is : [At. No.: \(Cr= 24,\,Mn= 25, \,Fe= 26, \,Co= 27\)]
- A \([Mn(H_2O)_6]^{2+}\) and \([Cr(H_2O)_6]^{2+}\)
- B \([CoCl_4]^{2-}\) and \([Fe(H_2O)_6]^{2+}\)
- C \([Cr(H_2O)_6]^{2+}\) and \([CoCl_4]^{2-}\)
- D \([Cr(H_2O)_6]^{2+}\) and \([Fe(H_2O)_6]^{2+}\)
Answer & Solution
Correct Answer
(D) \([Cr(H_2O)_6]^{2+}\) and \([Fe(H_2O)_6]^{2+}\)
Step-by-step Solution
Detailed explanation
magnetic moment \(\mu=\sqrt{n(n+2)}\) where \(n\) is the number of unpaired electrons. \(C r^{2+}\) and \(F e^{2+}\) has same number of unpaired electrons \(C r^{2+} \Rightarrow 3 d^{4}\) four unpaired electrons \(F e^{2+} \Rightarrow 3 d^{6}\) four unpaired electrons
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