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JEE Mains · Chemistry · STD 12 - 2. Electrochemistry

નીચેની રીડક્શન પ્રક્રિયાઓને ધ્યાનમાં લો \(Zn^{2+} + 2e^-\) \(\longrightarrow\) \(Zn (s) ; E^o = -0.76\,V\) \(Ca^{2+} + 2e^-\) \(\longrightarrow\) \(Ca (s) ; E^o = -2.87\,V\) \(Mg^{2+} + 2e^-\) \(\longrightarrow\) \(Mg (s) ; E^o = -2.36\,V\) \(Ni^{2+} + 2e^-\) \(\longrightarrow\) \(Ni (s) ; E^o = -0.25\,V\) ધાતુઓની રિડક્શનકર્તા ઉર્જાનો ચઢતો ક્રમ કયો થશે?

  1. A \(Ca < Zn < Mg < Ni\)
  2. B \(Ni < Zn < Mg < Ca\)
  3. C \(Zn < Mg < Ni < Ca\)
  4. D \(Ca < Mg < Zn < Ni\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(Ni < Zn < Mg < Ca\)

Step-by-step Solution

Detailed explanation

Lesser the \(SRP\) value higher the reducing power.
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