JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
Consider the following \(Zn^{2+} + 2e^-\) \(\longrightarrow\) \(Zn (s) ; E^o = -0.76\,V\) \(Ca^{2+} + 2e^-\) \(\longrightarrow\) \(Ca (s) ; E^o = -2.87\,V\) \(Mg^{2+} + 2e^-\) \(\longrightarrow\) \(Mg (s) ; E^o = -2.36\,V\) \(Ni^{2+} + 2e^-\) \(\longrightarrow\) \(Ni (s) ; E^o = -0.25\,V\) The reducing power of the metals increases in the order
- A \(Ca < Zn < Mg < Ni\)
- B \(Ni < Zn < Mg < Ca\)
- C \(Zn < Mg < Ni < Ca\)
- D \(Ca < Mg < Zn < Ni\)
Answer & Solution
Correct Answer
(B) \(Ni < Zn < Mg < Ca\)
Step-by-step Solution
Detailed explanation
Lesser the \(SRP\) value higher the reducing power.
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