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JEE Mains · Chemistry · STD 12 - 2. Electrochemistry

निम्न अपचयन प्रक्रमों पर विचार कीजिए \(Zn ^{2+}+2 e ^{-} \rightarrow Zn ( s ) ; E ^{0}=-0.76 \,V\) \(Ca ^{2+}+2 e ^{-} \rightarrow Ca ( s ) ; E ^{0}=-2.87 \,V\) \(Mg ^{2+}+2 e ^{-} \rightarrow Mg ( s ) ; E ^{0}=-2.36 \,V\) \(Ni ^{2+}+2 e ^{-} \rightarrow Ni ( s ) ; E ^{ o }=-0.25 \,V\) धातुओं की अपचायक सामर्थ्य इस क्रम में बढ़ेगी

  1. A \(Ca < Zn < Mg < Ni\)
  2. B \(Ni < Zn < Mg < Ca\)
  3. C \(Zn < Mg < Ni < Ca\)
  4. D \(Ca < Mg < Zn < Ni\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(Ni < Zn < Mg < Ca\)

Step-by-step Solution

Detailed explanation

Lesser the \(SRP\) value higher the reducing power.
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