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JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry

નીચે આપેલ સાચું વલણ ઓળખો. (પરમાણ્વીય ક્રમાંક \(= Ti : 22,\) \(Cr : 24\) અને \(Mo : 42\) )

  1. A \({{[Cr{{({{H}_{2}}O)}_{6}}]}^{2+}}>\,{{[Mo{{({{H}_{2}}O)}_{6}}]}^{2+}}\) નો \({\Delta _0}\) અને \({[Ti{({H_2}O)_6}]^{3 + }} > {[Ti{({H_2}O)_6}]^{2 + }}\) નો \({\Delta _0}\)
  2. B \({[Cr{({H_2}O)_6}]^{2 + }} > {[Mo{({H_2}O)_6}]^{2 + }}\) નો \({\Delta _0}\) અને \({[Ti{({H_2}O)_6}]^{3 + }} < {[Ti{({H_2}O)_6}]^{2 + }}\) નો \({\Delta _0}\)
  3. C \({[Cr{({H_2}O)_6}]^{2 + }} < {[Mo{({H_2}O)_6}]^{2 + }}\) નો \({\Delta _0}\) અને \({[Ti{({H_2}O)_6}]^{3 + }} > {[Ti{({H_2}O)_6}]^{2 + }}\) નો \({\Delta _0}\)
  4. D \({[Cr{({H_2}O)_6}]^{2 + }} <  {[Mo{({H_2}O)_6}]^{2 + }}\) નો \({\Delta _0}\) અને \({[Ti{({H_2}O)_6}]^{3 + }} < {[Ti{({H_2}O)_6}]^{2 + }}\) નો \({\Delta _0}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \({[Cr{({H_2}O)_6}]^{2 + }} < {[Mo{({H_2}O)_6}]^{2 + }}\) નો \({\Delta _0}\) અને \({[Ti{({H_2}O)_6}]^{3 + }} > {[Ti{({H_2}O)_6}]^{2 + }}\) નો \({\Delta _0}\)

Step-by-step Solution

Detailed explanation

The splitting is affected by the oxidation state of the central metal ion. A higher oxidation state leads to larger spitting hence. \({\Delta _0}\) of \({{[Ti{{({{H}_{2}}O)}_{6}}]}^{3+}}>\) \({\Delta _0}\) of \({{[Ti{{({{H}_{2}}O)}_{6}}]}^{2+}}\) Further \({\Delta _0}\) also…
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