JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry
Identify the correct trend given below (Atomic No. \(= Ti : 22,\) \(Cr : 24\) and \(Mo : 42\) )
- A \({\Delta _0}\) of \({{[Cr{{({{H}_{2}}O)}_{6}}]}^{2+}}>\,{{[Mo{{({{H}_{2}}O)}_{6}}]}^{2+}}\) and \({\Delta _0}\) of \({[Ti{({H_2}O)_6}]^{3 + }} > {[Ti{({H_2}O)_6}]^{2 + }}\)
- B \({\Delta _0}\) of \({[Cr{({H_2}O)_6}]^{2 + }} > {[Mo{({H_2}O)_6}]^{2 + }}\) and \({\Delta _0}\) of \({[Ti{({H_2}O)_6}]^{3 + }} < {[Ti{({H_2}O)_6}]^{2 + }}\)
- C \({\Delta _0}\) of \({[Cr{({H_2}O)_6}]^{2 + }} < {[Mo{({H_2}O)_6}]^{2 + }}\) and \({\Delta _0}\) of \({[Ti{({H_2}O)_6}]^{3 + }} > {[Ti{({H_2}O)_6}]^{2 + }}\)
- D \({\Delta _0}\) of \({[Cr{({H_2}O)_6}]^{2 + }} < {[Mo{({H_2}O)_6}]^{2 + }}\) and \({\Delta _0}\) of \({[Ti{({H_2}O)_6}]^{3 + }} < {[Ti{({H_2}O)_6}]^{2 + }}\)
Answer & Solution
Correct Answer
(C) \({\Delta _0}\) of \({[Cr{({H_2}O)_6}]^{2 + }} < {[Mo{({H_2}O)_6}]^{2 + }}\) and \({\Delta _0}\) of \({[Ti{({H_2}O)_6}]^{3 + }} > {[Ti{({H_2}O)_6}]^{2 + }}\)
Step-by-step Solution
Detailed explanation
The splitting is affected by the oxidation state of the central metal ion. A higher oxidation state leads to larger spitting hence. \({\Delta _0}\) of \({{[Ti{{({{H}_{2}}O)}_{6}}]}^{3+}}>\) \({\Delta _0}\) of \({{[Ti{{({{H}_{2}}O)}_{6}}]}^{2+}}\) Further \({\Delta _0}\) also…
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