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JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry

\({KCl}\) માટે બોર્ન-હેબર ચક્રનું મૂલ્યાંકન નીચેની માહિતી સાથે કરવામાં આવે છે: \(\Delta_{f} {H}^{\ominus}\) \({KCl}=-436.7 \,{~kJ}\, {~mol}^{-1}\) \(\Delta_{\text {sub }} {H}^{\ominus}\) \({K}=89.2 \,{~kJ}\, {~mol}^{-1}\) \(\Delta_{\text {ionization }} \,{H}^{-}\) \({K}=419.0\, {~kJ}\, {~mol}^{-1}\) \(\Delta_{\text {electron gain }} {H}^{\ominus}\) \({Cl}_{(\text {e) }}=-348.6 \,{~kJ} \,{~mol}^{-1}\) \(\Delta_{{bond}} {H}^{-}\) \({Cl}_{2}=243.0 \,{~kJ} \,{~mol}^{-1}\) \({KCl}\)ની લેટિસ એન્થાલ્પીની તીવ્રતા \(.....\) \({kJ} {mol}^{-1}\) છે.

  1. A \(718\)
  2. B \(951\)
  3. C \(632\)
  4. D \(521\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(718\)

Step-by-step Solution

Detailed explanation

\(\Delta_{{f}} {H}_{{KCl}}^{\Theta}=\Delta_{\text {sub }} {H}_{({K})}^{\Theta}+\Delta_{\text {ionization }} {H}_{({K})}^{\Theta}+\frac{1}{2} \Delta_{{bond}} {H}_{\left({Cl}_{2}\right)}^{\Theta}\)…
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