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JEE Mains · Chemistry · STD 11 - 2. structure of atom

જો  \(\lambda_0\) અને \(\lambda\) અનુક્રમે દેહલીજ તરંગલંબાઈ  આપાત પ્રકાશની તરંગલંબાઈ હોય તો ધાતુની સપાટી પરથી મુક્ત થતા ફોટોઇલેક્ટ્રોનનો વેગ જણાવો.

  1. A \(\sqrt {\frac{{2h}}{m}\left( {{\lambda _0} - \lambda } \right)} \)
  2. B \(\sqrt {\frac{{2hc}}{m}\left( {{\lambda _0} - \lambda } \right)} \)
  3. C \(\sqrt {\frac{{2hc}}{m}\left( {\frac{{{\lambda _0} - \lambda }}{{\lambda {\lambda _0}}}} \right)} \)
  4. D \(\sqrt {\frac{{2h}}{m}\left( {\frac{1}{{{\lambda _0}}} - \frac{1}{\lambda }} \right)} \)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\sqrt {\frac{{2hc}}{m}\left( {\frac{{{\lambda _0} - \lambda }}{{\lambda {\lambda _0}}}} \right)} \)

Step-by-step Solution

Detailed explanation

The kinetic enegry of the ejected electron is given by the equation \(hv = h{v_0} + \frac{1}{2}m{v^2}\,\,\,\because \,v = \frac{c}{\lambda }\) or \(\frac{{hc}}{\lambda } = \frac{{hc}}{{{\lambda _0}}} + \frac{1}{2}m{v^2}\)…
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