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JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)

\(27^{\circ}\,C\) અને \(1\)વાતા.દબાણ પર,\(SO _{2( g )}+\frac{1}{2} O _{2( g )} \rightleftharpoons SO _{3( g )}\) પ્રક્રિયા માટે,\(K _{ p }=2 \times 10^{12}\) છે.આ જ પ્રક્રિયા માટે \(K_c .............\times 10^{13}\) છે.(નજીકનો પૂર્ણાંક)(આપેલ \(R =0.082\,L\,atm\,K ^{-1}\,mol ^{-1}\))

  1. A \(2\)
  2. B \(3\)
  3. C \(4\)
  4. D \(1\)
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Answer & Solution

Correct Answer

(D) \(1\)

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Detailed explanation

\(SO _{2( g )}+\frac{1}{2} O _{2( g )} \rightleftharpoons SO _{3( g )}\) \(K _{ P }=2 \times 10^{12} \text { at } 300\,K\) \(K _{ P }= K _{ C } \times( RT )^{\Delta n _{ g }}\) \(2 \times 10^{12}= K _{ C } \times(0.082 \times 300)^{-1 / 2}\) \(K _{ C }=9.92 \times 10^{12}\)…
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