ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry

\(0.5\, {M}\, {NaOH}\) \(250\, {~mL}\)ને \(500\, {~mL}\) \(1\, {M}\, {HCl}\) ઉમેરવામાં આવ્યુ છે. સંપૂર્ણ પ્રક્રિયા પછી દ્રાવણમાં બિનપ્રક્રિયકૃત \({HCl}\) પરમાણુની સંખ્યા \(......\,\times 10^{21}\) છે. (નજીકના પૂર્ણાંકમાં) \(\left({N}_{{A}}=6.022 \times 10^{23}\right)\)

  1. A \(226\)
  2. B \(235\)
  3. C \(462\)
  4. D \(521\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(226\)

Step-by-step Solution

Detailed explanation

We known that no. of moles \(=\text { Vlitre } \times \text { Molarity and No. of millimoles }=V_{m l} \times \text { Molarity }\) \(\text { so millimoles of } {NaOH}=250 \times 0.5=125\) \(\text { Millimoles of } {HCl}=500 \times 1=500\) \(\text { Now reaction is }\)…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app