JEE Mains · Physics · STD 11 - 9.1 fluid mechanics
Two liquids of densities \(\rho_{1}\) and \(\rho_{2}\left(\rho_{2}=2 \rho_{1}\right)\) are filled up behind a square wall of side \(10\; \mathrm{m}\) as shown in figure. Each liquid has a height of \(5 \;\mathrm{m} .\) The ratio of the forces due to these liquids exerted on upper part \(MN\) to that at the lower pait \(NO\) is (Assume that the liquids are not mixing)
- A \(\frac 14\)
- B \(\frac 23\)
- C \(\frac 13\)
- D \(\frac 12\)
Answer & Solution
Correct Answer
(A) \(\frac 14\)
Step-by-step Solution
Detailed explanation
\(\mathrm{F}_{1}=\frac{\rho \mathrm{gh}}{2} \times \mathrm{A}\) \(\mathrm{F}_{2}=\left(\rho \mathrm{gh}+\frac{2 \rho \mathrm{gh}}{2}\right) \mathrm{A}\) \(\frac{\mathrm{F}_{1}}{\mathrm{F}_{2}}=\frac{1}{4}\)
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