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JEE Mains · Physics · STD 11 - 9.1 fluid mechanics
Water flows in a horizontal tube (see figure). The pressure of water changes by \(700\; \mathrm{Nm}^{-2}\) between \(\mathrm{A}\) and \(\mathrm{B}\) where the area of cross section are \(40\; \mathrm{cm}^{2}\) and \(20\; \mathrm{cm}^{2},\) respectively. Find the rate of flow of water through the tube. ........ \(\mathrm{cm}^{3} / \mathrm{s}\) (density of water \(=1000\; \mathrm{kgm}^{-3}\) )
- A \(1810\)
- B \(3020 \)
- C \(2720 \)
- D \(2420\)
Answer & Solution
Correct Answer
(C) \(2720 \)
Step-by-step Solution
Detailed explanation
Rate of flow of water \(=\mathrm{A}_{\mathrm{A}} \mathrm{V}_{\mathrm{A}}=\mathrm{A}_{\mathrm{B}} \mathrm{V}_{\mathrm{B}}\) \((40) \mathrm{V}_{\mathrm{A}}=(20) \mathrm{V}_{\mathrm{B}}\) \(\mathrm{V}_{\mathrm{B}}=2 \mathrm{V}_{\mathrm{A}}\) Using Bernoulli's theorem…
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