JEE Mains · Physics · STD 12 - 9. Ray optics and optical instruments
In an experiment to measure focal length \((f)\) of convex lens, the least counts of the measuring scales for the position of object \((u)\) and for the position of image \((v)\) are \(\Delta u\) and \(\Delta v\), respectively. The error in the measurement of the focal length of the convex lens will be _______.
- A \(\frac{\Delta \mathrm{u}}{\mathrm{u}}+\frac{\Delta \mathrm{v}}{\mathrm{v}}\)
- B \(f^2\left[\frac{\Delta u}{u^2}+\frac{\Delta v}{v^2}\right]\)
- C \(2 \mathrm{f}\left[\frac{\Delta \mathrm{u}}{\mathrm{u}}+\frac{\Delta \mathrm{v}}{\mathrm{v}}\right]\)
- D \(f\left[\frac{\Delta u}{u}+\frac{\Delta v}{v}\right]\)
Answer & Solution
Correct Answer
(B) \(f^2\left[\frac{\Delta u}{u^2}+\frac{\Delta v}{v^2}\right]\)
Step-by-step Solution
Detailed explanation
\(f^{-1}=v^{-1}-u^{-1}\) \(-f^{-2} d f=-v^{-2} d v-u^{-2} d u\) \(\frac{d f}{f^2}=\frac{d v}{v^2}+\frac{d u}{u^2}\) \(d f=f^2\left[\frac{d v}{v^2}+\frac{d u}{u^2}\right]\)
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