ExamBro
ExamBro
JEE Mains · Physics · STD 11 - System of particles and rotational motion
  • JEE Mains 2023
  • Medium
  • MCQ

A child of mass \(5\,kg\) is going round a merry-goround that makes \(1\) rotation in \(3.14\,s\). The radius of the merry-go-round is \(2\,m\). The centrifugal force on the child will be \(.......\,N\)

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(D) \(40\) \(N\)

Step-by-step Solution

Detailed explanation

\(\omega=\frac{2 \pi}{3.14}=2\,rad / s\)

\(\left|\bar{f}_{\text {centrifiugal }}\right|=\left|-m \bar{a}_{\operatorname{Re} f .}\right|\)

\(=M \omega^2 R\)

\(=40\,N\)

Same subject
Explore more questions on app