JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance
A parallel plate capacitor is formed by two plates each of area \(30 \pi\, cm ^{2}\) separated by \(1\, mm\). A material of dielectric strength \(3.6 \times 10^{7} \,Vm ^{-1}\) is filled between the plates. If the maximum charge that can be stored on the capacitor without causing any dielectric breakdown is \(7 \times 10^{-6}\, C\), the value of dielectric constant of the material is \(\left\{ Use : \frac{1}{4 \pi \varepsilon_{0}}=9 \times 10^{9} Nm ^{2} C ^{-2}\right\}\)
- A \(1.66\)
- B \(1.75\)
- C \(2.25\)
- D \(2.33\)
Answer & Solution
Correct Answer
(D) \(2.33\)
Step-by-step Solution
Detailed explanation
\(K =\frac{ q }{ A \in_{0} E }=\frac{7 \times 10^{-6}}{30 \pi \times 10^{-4} \times \frac{1}{4 \pi \times 9 \times 10^{9}} \times 3.6 \times 10^{7}}\) \(K =\frac{36 \times 7}{30 \times 3.6}=2.33\)
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