JEE Mains · Physics · STD 11 - 11. thermodynamics
Two different adiabatic paths for the same gas intersect two isothermal curves as shown in\(P-V\) diagram. The relation between the ratio \(\frac{V_a}{V_d}\) and the ratio \(\frac{V_b}{V_c}\) is _______.
- A \(\frac{V_a}{V_d}=\left(\frac{V_b}{V_c}\right)^{-1}\)
- B \(\frac{V_a}{V_d} \neq \frac{V_b}{V_c}\)
- C \(\frac{V_a}{V_d}=\frac{V_b}{V_c}\)
- D \(\frac{V_a}{V_d}=\left(\frac{V_b}{V_c}\right)^2\)
Answer & Solution
Correct Answer
(C) \(\frac{V_a}{V_d}=\frac{V_b}{V_c}\)
Step-by-step Solution
Detailed explanation
For adiabatic process \(\mathrm{TV}^{\gamma-1}=\text { constant }\) \(\mathrm{T}_{\mathrm{a}} \cdot \mathrm{V}_{\mathrm{a}}^{\gamma-1}=\mathrm{T}_{\mathrm{d}} \cdot \mathrm{V}_{\mathrm{d}}^{\gamma-1}\)…
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